A Quadrilateral Challenge

Here’s an easy-to-understand, remarkably rich question that arose during a recent Math for America “Bring Your Own Math” workshop.

If a quadrilateral has a pair of opposite, congruent sides and a pair of opposite, congruent angles, is it a parallelogram?

I had a lot of fun thinking about this problem on my own, discussing it with colleagues, and sharing it with students.  At different times throughout the process, I felt strongly about incompatible answers to the question.  For me, that is a characteristic of a good problem.

I encourage you to play around with this.  I was surprised at how many cool ideas came out as I worked my way through this problem, and I look forward to sharing them!

And if you want to see a solution, click here.

Another Equilateral Comparison

The passing of consecutive isosceles triangle days has me once again thinking about the question “Which Triangle is More Equilateral?”

I first considered the question on 10/10/11, comparing the 10-10-11 triangle and the 10-11-11 triangle.  After a spirited discussion, I offered one approach to the question here.  The problem gave me lots to think about, both mathematically and pedagogically, and I reflected on what I liked about this problem here.

But as 12/11/11 and 12/12/11 pass, I thought I’d revisit my strategy for answering the question “Which triangle is more equilateral?”

My basic strategy, outlined in more detail here, is to ultimately to quantify the circleness of each triangle.  To me, being equilateral is all about trying to be as much like a circle as possible.  So I created a measure to determine how close to circlehood a triangle is.  Here are the numbers.

The 11-12-12 triangle’s measure is closer to 1, thus making it the more equilateral triangle.

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48,647th St and 16,398th Ave

This is a fun and whimsical mathematical application:  an extension of the Manhattan grid systems to every location on Earth!

http://extendny.com/

Find Brasilia at South 39,688 St and East 25,424 Ave, Bangalore at 84,097 St and East 77,224 Ave, or  Bora Bora at the corner of 41,214 Ave and S 69,342 St.

I wonder how much the cab fare would be from midtown Manhattan to South 43,892 St and East 71,247 Ave?

11/11/11 — Equilateral Triangle Day!

While others celebrate the number 11 on this special day, I prefer to honor the Equilateral Triangle.

Last year, on 10/10/10, I celebrated the symmetry of the equilateral triangle.  This year, I offer a favorite Proof Without Words.  Well, a proof with some words.  In any event, we will use equilateral triangles to prove that the following infinite series

\frac{1}{4} +  \frac{1}{16}  +  \frac{1}{64}  + \frac{1}{256}  +  . . .

is \frac{1}{3}.

Consider the following diagram.

Notice that the largest blue equilateral triangle is \frac{1}{4} the area of the entire equilateral triangle.  The next largest blue triangle is \frac{1}{4} of \frac{1}{4}, or \frac{1}{16} of the entire triangle.  The next largest blue triangle is \frac{1}{64} of the original triangle, and so on.

So, the sum of the blue triangles is

\frac{1}{4} +  \frac{1}{16}  +  \frac{1}{64}  + \frac{1}{256}  +  . . .

Let’s call this S.

Now, here’s the magic:  the sum of the red triangles is also S!  This is true because for every blue triangle, there is a congruent red triangle right next to it.  Similarly, the sum of the yellow triangle is also S.

When you put all the blue, red, and yellow triangles together, you get the original triangle, whose area is 1.  Thus, 3S = 1, and so

S = \frac{1}{3}

Therefore, we have

\frac{1}{4} +  \frac{1}{16}  +  \frac{1}{64}  + \frac{1}{256}  +  . . .  = \frac{1}{3}

Happy Equilateral Triangle Day!

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The 11-10-11 Triangle

Today’s date, 11-10-11, reminded me to re-visit a recent post that posed the question “Which triangle is more equilateral:  the 10-10-11 triangle, or the 10-11-11 triangle?”

The original post elicited lots of great comments from readers, who weighed in on what they thought the question meant and how they might go about trying to answer it.  I offered one approach, and an answer to the question, in this follow up post.

As a math teacher, there are many reasons I try to create problems like this.  Here are a few that I think are important.

First and foremost, in order to address this question, a significant amount of thought must be put into deciding what the question means.  This process involves analysis, synthesis, reflection, and ideally discussion, all of which will be substantially mathematical in nature.

A second, related, virtue is that there is no obviously correct interpretation of what this question means.  Mathematics is often viewed in stark terms:  answers are either right or wrong.  But the certitude of mathematics comes only after we agree on mathematical models for our given problem.  There is often great debate about what those models should look like; the history of mathematics is full of such debate.

Problems like this one invite students into the modelling process, where they can discuss and debate the validity of various approaches.  Moreover, the problem allows solvers to create multiple different models to explore, compare, and contrast.  And in the end, we can pose and explore meta-mathematical question like “Which model most closely aligns with our intuitions?” and “Which model is the most useful?”

Lastly, this problem demonstrates one role creativity plays in mathematics.  A simple response to the question, one I heard many times, is “Neither of these triangles are equilateral.  They are both equally unequilateral.”  Given our rigid definition of what equilateralmeans, this response is technically correct.  But by relaxing our ideas about equilateral, by allowing ourselves to ponder what the phrase “more equilateral” might mean, by thinking creatively about what kinds of questions we can ask, we create an opportunity to explore, and possibly uncover, some new mathematical ideas.

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