Cross-Section of a Run, Part II

Recently I posted two photos of a runner taken 1.1 seconds apart and asked readers to speculate as to how fast he was running.  Here is one proposed solution.

Using a photo utility, I merged to two photos into one. new runners 1

You can definitely see the seam between the two photos, but what’s important here is that the geometry of the two photos seems consistent.  In other words, I claim that I haven’t altered any distances by pasting the two pictures together.

I then used the photo utility to measure in pixels the distance between two similar points on the runner and the runner’s height.  The orange lines are here to illustrate the measurements.

new runners 2

The distance from hip-to-hip is about 650 pixels.  Since the photos were taken 1.1 seconds apart, this means that the runner’s pace is around 650 / 1.1 , or 590 pixels per second.

The runner’s height is 380 pixels.  How tall do we think the runner is in real life?  Well, he doesn’t look that tall, and he’s hunched over a bit in his runner’s stance.  I’m estimating his height, the vertical orange bar, to be around 5.75 feet.   This gives us the following scale factor:  380 pixels is about 5.75 feet.

We can now easily convert the rate from pixels per second into feet per second.  Using the above scale factor, 590 pixels should be around 8.93 feet, so the runner’s speed is approximately 8.93 feet per second.  Now that we have a meaningful rate to work with, we can easily complete the problem with some straightforward calculations.

So how long will it take to run a mile at this rate?  By my calculation, about 9.86 minutes.

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Coffee, Cream, and Making a Wish

We have looked at several solutions to the classic Coffee and Cream mixture problem:

Suppose you have a cup of coffee and a cup of cream.  If you take a spoonful of cream, mix it up with the coffee, then take a spoonful of that mixture and add it back to the cream, is there more cream in the coffee, or more coffee in the cream? 

I offered a solution that begins by making a wish.  That is, I wished that each cup initially contained 10 spoonfuls of liquid; then I proceed to solve the problem algebraically, by following spoonfuls of liquid back and forth between cups.  To illustrate the real power of the make-a-wish strategy, though, let’s wish that each cup started with one spoonful of liquidcoffee and cream extreme case 1In this case, the act of transferring one spoonful of cream into the coffee amounts to pouring all the cream in the coffee. coffee and cream extreme case 2Now, mix it up.  The mixture on the left is obviously half coffee and half cream. coffee and cream extreme case 3Now, pour a spoonful of the mixture, or half, back into the empty cup.   coffee and cream extreme case 4The two cups now contain exactly the same solution:  half coffee, and half cream!  So the answer to the question is obviously that there are equal amounts of cream in the coffee and coffee in the cream!

Be sure to check out the elegant solution to the problem, as well!

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Inforgraphic Competition

visualization magazineVisualisation Magazine, which seems to specialize in Data Representation and Information Graphics, is holding a homemade, handmade Infographic Contest.

The contest is apparently open to anyone, and the publishers are emphasizing handmade techniques.  The winner will make the cover of the next volume of their magazine.  I leafed through their volume on Circles (screenshot above) and there were some good looking infographics in there.

There is a flickr group set up for submissions, which you can check out here:  http://www.flickr.com/groups/vismaghandmadecontest.

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